Question

A ball thrown vertically upward with a speed of 19.6 metre per second from the top of a tower returns to the earth in 6 second find the height of the tower

Answer 1

A ball is thrown upward with velocity 19.6 M per second.....
while going office experience a gravitational force which is against of it....
so to calculate time now over here we use equation has
V=u+at
fire velocity is zero initial velocity is 19.6 acceleration is equal to -9.8 and time is t..
so we get 30 call to 2 second...
ball reaches highest point in 2 second...
now the distance travelled by the ball to reach the highest points
S=ut+atsquare /2
by substituting a value we get as a sequel to 58.8 M....
now the ball has to come down so its experience gravitational force which is positive.. I mean along the force of gravitation...
Ash wartortle time is 6 second in which it take 2 seconds to go of Saravanan time is 4 seconds.....
no time takes to reach the ball to the ground is equal to S is equal to UT plus half a t square...
by substituting the value is equal to we get as 9.8 into 8 metre....
show the height of Tower is equal to 9.8 into 8 - 58.8...
answer is 49 m