A ball thrown vertically upward with speed 19.6 m per second from a top of a tower and return to the earth in 6 second find the height of the tower
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If ball is thrown upwards,
then it can be derived that,
H = - ut + at^2/2
(u= 19.6 m/s= 2g m/s)
Thus,
H = - 12g + 18g = 6g
Height of tower is 58.8 m
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