Question

a ball thrown vertically upwards reaches a highest of 80 m. calculate:
A. the time to reach the highest point
B. the speed of ball upon arrival on the ground

Answer 1

option A ............

Answer 2

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Here is your answer goes like this :

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Your question :A ball thrown vertically upwards reaches a highest of 80 m. calculate:
A. the time to reach the highest point
B. the speed of ball upon arrival on the ground


Answer:A
Position of the ball after 10s = -80m ( minus sign as the ground is downwards from the origin).
Using the relation,
s = u t + ½ a t²
In this equation s= -80m, u=?, a = -10 m/s²; t=10s. Substituting in the equation we get,
-80 m = 10 u - ½ ×(10 m/s²)×100s²
=> -80 m = 10 u - 500 m
=> 10 u = 420,; u = 42 m/s.
The ball was projected with a velocity of 42 m/s directed upwards.



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