A ball thrown vertically upwards return to its starting point in 4s. If g= 10 m/s^2 , find its initial speed.
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EXPLANATION:-
Here V=0
U=?
a=-10m/s^-1
Therefore from this we can say it take 2 second to rise to maximum height and in next 2 second it falls from maximum height to the position where it is thrown(this is because time of accent = time of decent).
So using first equation of motion:-
v=u+at
0=u+(-10)(2)
0=u-20
u=20 m/s
So the initial velocity is 20 m/s
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1
Answer:
20m/s^ if u need explaination see the above picture
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