a ball thrown vertically upwards returns to the thrower in 20. calculate the velocity with which the ball was thrown and the maximum height attained by the ball.{video}
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Answer:
Explanation:
given time of flight is 20s.
when the ball is thrown vertically upwards it reaches the maximum height with final velocity 0.
we know that time of ascent = time of descent
therefore time of ascent is 10 s
and the time of ascent = u/g
therefore 10= u/10
so initial velocity with which it is thrown is 100 m/s.
max height is 1/2 gt^2
max height attained = 500m
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