Question

A ball thrown vertically upwards returns to the thrower in 20sec. Calculate the velocity with which it was thrown and the maximum height attained by the ball. Take g=10m/s^2

Answer 1

Answer:

Explanation:

time of flight(given) = 20s

2u/g = 20s

2u = 20s *g = 20 * 10

2u = 200 m/s

So,

u = 200/2 = 100m/s

Now,

maximum height = u²/2g

                            = 100²/2*10 = 10,000/20 = 500m

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