Question

A ball thrown vertically upwards takes 4s to return to the ground. Calculate the maximum height reached and the velocity with which it was thrown upward.

Answer 1

Answer:

h = 20m and u = 20 m/s

Explanation:

Time of ascend = Time of descend

Time of ascend + Time of descend = 4 sec

Time of ascend= Time of descend = 2 sec

Velocity at the highest point(v) = 0 m/s

Accerlation = g = -10 m/s

v= u+gt. (First Equation of Motion)

0 = u - 10(2)

u = 20 m/s

h = ut + 1/2at^2

h= 20(2) - 1/2 (10)(2)(2)

h = 40 - 20

h = 20 m