Question

A ball thrown vertically upwards with a speed of 19.6 m/s from the top of a tower returns to the earth in 6s.then find height of the tower?

Answer 1

we have to find the distance the ball covered as it is the height of the tower that the ball covered
So we will use the equation of motion
s=ut+1/2at square
so,
u=0(as it was thrown, the initial velocity was 0 before throwing
a=19.6
t=6
so,. s=0(6)+1/2(19.6)(6)(6)
s=0+9.8(36)
s=352.8m

therefore height of the tower is 352.8metres

HOPE THIS HELPS

Answer 2

Answer:we have to find the distance the ball covered as it is the height of the tower that the ball covered

So we will use the equation of motion

s=ut+1/2at square

so,

u=0(as it was thrown, the initial velocity was 0 before throwing

a=19.6

t=6

so,. s=0(6)+1/2(19.6)(6)(6)

s=0+9.8(36)

s=352.8m

therefore height of the tower is 352.8metres

Explanation:

hope its help you