Question

a ball thrown vertically upwards with a speed of 19.6m/s from the top of tower and return to the earth in 6 s find the height of tower(g=9.8m/s) ​

Answer 1

Answer:

58.8m

Explanation:

Taking upward direction to be positive

u = 19.6m / s

t = 6s

a=-g=-9.8m/s^2

Displacement of the ball=-h

Applying s=ut+(at^2)/2

-h=19.6(6)+(-9.8)(36)/2

h = 58.8m

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