A ball thrown vertically upwards with a speed of 20 ms^-1 from the top of a tower returns to the earth in 8 s. Find the height of the tower. Take g — 10 ms^-2
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Answer: 160m
Explanation:
The time taken for ball to return to Earth = 8 sec
The maximum height achieved at time = Total time taken /2
=8/2 = 4sec
u=20m/s
t=4sec
a=10m/sec^2
s=?
s = ut + 1/2 a t^2
=20 * 4 + 1/2 * 10 * 4^2
= 80 + 80
= 160m
Hope this helps
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