Question

A ball thrown vertically upwards with a speed of V

attains a height h1. Another ball thrown upwards

from the same point with a speed of 2V attains a

height h2. Then, h2 is equal to​

Answer 1

Explanation:

if a object thrown with speed v it attains height h1

if a object throws with speed 2V it attains height h2

As we know time is equal to

t=√(2h/g)

as we know speed =distance by time taken

speed =distance÷time taken

from this formula time=distance÷speed

substitute this formula in t

distance÷speed=√(2h/g)

so h1÷V=√(2h1/g)

so do squaring on both side

(h1)^2÷(V)^2=2h1÷g

as, (h2)^2÷4V^2=2h2÷g

if we divide these both equations

(4h1)^2÷(h2)^2=h1÷h2

by this, 4h1=h2

so, h2=4h1

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