Question

A ball thrown vertically upwards with a velocity of 10 m/s . calculate the height attain by ball and time taken by it to reach the highest point if the acceleration of ball is -10 m/s power2 during its motion.​

Answer 1

Answer:

The final velocity it will reach with the acceleration of 10ms is 14ms. And the time taken by the ball to reach its highest point is 1.43 seconds.

Explanation:

$distance \: travelled = s = 10 \\ final \: velocity = v = 0ms$

Using,

${v}^{2} - {u}^{2} = 2gs \\ {u}^{2} = 196 \\ u = 14ms$

where u is the velocity with which the object is thrown upwards.

Using,

$v = u + gt \\ t = \frac{v - u}{g} = 1.43sec$