a ball thrown vertically upwards with a velociy of 15 ms calculate the maximum height reach by ball
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➡️initial velocity ,u=15m/s
➡️at maximum height it reaches, it's velocity will be 0 m/s
➡️acceleration will be -g
according to the equation,
2as = v^2-u^2
we have,
s = (0-15×15)/2×-9.8
s= -225/-19.6
s = 2250/196
s = 1125/98 = 11.48
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