Physics, asked by shumailasoomro450, 6 months ago

a ball tied at one end of string of length 50cm is whirled in a horizontal circle with an angular speed of 10 rad/s its ac ​

Answers

Answered by satyaprakashprabhuji
0

Explanation:

Radius =r=50cm=0.5m

In 20 sec revolution =10

In 1 sec revolution =10/20=1/2 Hz

N=1/2Hz

Now,

Angular velocity =W=2πn=w=2×3.14×0.5

Radial Acceleration =w

2

r

Radial Acceleration =(3.14)

2

×0.5m/s

2

=4.93m/s

2

=493cm/s

2

Answered by shylajakgp82
0

Answer:

ANSWER

Radius =r=50cm=0.5m

In 20 sec revolution =10

In 1 sec revolution =10/20=1/2 Hz

N=1/2Hz

Now,

Angular velocity =W=2πn=w=2×3.14×0.5

Radial Acceleration =w

2

r

Radial Acceleration =(3.14)

2

×0.5m/s

2

=4.93m/s

2

=493cm/s

2

Explanation:

hope this helps u friend

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