A ball town down vertically with an initial speed of 20 m/s from. a height of 60 m. Find
(i) its speed just before it strikes ithe ground.
ii) how long it takes for the ball
to reach the ground.
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Step-by-step explanation:
The solution is pretty simple and you can get it by working on equations of motion.
You throw a ball vertically upwards and the ball will travel a distance of ‘h’ (vertically) before attaining zero velocity. Then it will continue its journey, falling with constant acceleration.
The velocity at point-1 and point-3 will be the same.
Therefore, u(1) = u(2) = u (which is to be calculated or found).
We have,
v = u + (g * t)
v = u + (10 m/sq. sec * 10 sec)
v = u + 100 ………………………..(EQUATION 1)
And,
Substituting the value of v (from eqn-1) in above,
Substituting g = 10 m/sq. sec, and s = 80 m,
You will have the value of initial velocity (u) as 42 m/s.
Hopefully, this helps.
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