Question

A ball travelling in straight line with initial velocity 48m/s and acceleration -10 m/s find dost travelled in 5 Th second

Answer 1

Answer:

distance travelled in n th second = u + a/2 (2n - 1)

48 + -10/2(2*5 - 1)

48 + -5*9

48 - 45

3 m

thus 3m is travelled in the 5th second