Physics, asked by clickbaitrii182006, 2 months ago

A BALL WAS THROWN UP FROM A POINT 'A' AND REACHES THE HIGHEST POINT 'H'
THEN:-
i) K.E. AT 'A' IS EQUAL TO K.E. AT 'H'
ii) P.E. AT 'A' IS EQUAL TO K.E. AT 'H'
iii) K.E. AT 'A' IS EQUAL TO P.E. AT 'H'
iv) P.E. AT 'A' IS EQUAL TO P.E. AT 'H'

ALSO EXPLAIN WHY

Answers

Answered by ushmon
0

Answer:

As it is at maximum height it will have only potential energy no kinetic energy because of zero velocity. Hence P.E=mgh

But when it is on the ground it has no height from the ground hence P.E is zero where K.E has a value of mgh because energy is conserved at every point.

Hence, option D is the correct answer.

Explanation:

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Answered by SanaArmyGirl
26

Answer:

As it is at maximum height it will have only potential energy or kinetic energy because of velocity .Hence P.E=mgh

But when it is on the ground it has no height from the ground hence P.E is zero where K.E has a value of mgh because energy is conserved at every point

Explanation:

4 th option is ur Answer

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