Physics, asked by headlongdread6000, 5 days ago

A ball was thrown upward from top of a building 19.37 m high with velocity of 24.5 m/s. If ball was moved by wind just enough to miss the building, and landed on ground below the building. How long was it in the air? Take g = 9.8 m/s²​

Answers

Answered by chakrobortyjeet44
0

T=2u/g

use this formula

2*24.5/9.8= 5s

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