Question

A ball weighing 10 g hits a hard surface vertically
with a speed of 5 m/s and rebounds with the same
speed. The ball remains in contact with the surface
for (0.01) s. The average force exerted by the
surface on the ball is :-





help help....just confused....​

Answer 1

first of all change gram into kg

then find acelaration then

then apply the value in formula

F=ma

then u will get the ans.

Answer 2

average force=change in momentum/

time duration of change

in momentum

=2*0.01*5/0.01

=10N