Question

A ball weighing 2 kg dropped from a height takes 2 seconds to reach the ground. Calculate the velocity just when it touches the ground. pls help with explanation asap for exam​

Answer 1

Answer:

Given,

Displacement, s=6m

Time, t=0.2sec

Apply kinematic equation of motion

s=ut+

2

1

at

2

6=u(0.2)+

2

1

×10×(0.2)

2

u=29m/s

v=u+at

v=29+10×0.2=31m/s

It falls freely from some height h, where initial velocity, U=0

Apply second kinematic equation

V

2

−U

2

=2gh

h=

2g

V

2

=

2×10

31

2

=48.05m

From 48.05mball is dropped.

Explanation:

IN OTHER WAY BUT IT WILL HELP YOU I THINK