Physics, asked by Anonymous, 11 months ago

A ball weighing 4 kg of density 4000 kgm³ is completely immersed in a water of density 1000 kgm³. Find the force buoyancy on it and Take g as 10 m²​

Answers

Answered by BrainlyWriter
73

\Large\bold{\underline{\underline{Answer:-}}}

Given :

Weight of ball = 4 kg

Density of ball = 4000 kgm³

Density of water= 1000 kgm³

Buoyant Force = ?

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\bf\small\bold{\underline{\underline{Step-By-Step\:Explanation:-}}}

The buoyant force is given as

F = ρgV

F = 4/4000 × 10 × 1000 = 10

So, buoyant force will be 10 N

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Buoyant : Buoyant force is an upward force exerted by a fluid, which opposes the weight of an object in the fluid. Objects immersed in water observes a loss in weight due to the buoyant force.

Answered by ғɪɴɴвαłσℜ
13

Aɴꜱᴡᴇʀ

Buoyant Force on the ball is 10N

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Gɪᴠᴇɴ

Weight of ball = 4 kg

Density of ball = 4000 kgm³

Density of water= 1000 kgm³

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ᴛᴏ ꜰɪɴᴅ

The buoyant force

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Sᴛᴇᴘꜱ

The buoyant force can be found by

 \large \sf  \orange{f = pgv}

 \large \sf{}f =  \frac{4}{4000}  \times 10 \times 1000 \\  \\  \large \pink{ \dashrightarrow{} \tt{}f =  \huge \red{10n}}

Extra information

Buoyant force is an upward force exerted by a fluid, which opposes the weight of an object in the fluid. Objects immersed in water observes a loss in weight due to the buoyant force.

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\huge{\mathfrak{\purple{hope\; it \;helps}}}

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