Physics, asked by queensp73, 9 months ago

A ball weighing 4 kg of density 4000 kgm³ is completely immersed in a water of density 1000 kgm³. Find the force buoyancy on it and Take g as 10 m²​

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Answers

Answered by mondalarijit736
1

Answer:

Now, according to Archimedes principle, the upthrust is equal to the weight of water displaced. Mass of ball m = 4 kg Density of ball ρ = 4000 kg/m3 Volume of the ball V = m/ρ = 4/4000 m3 = 10-3 m3

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Answered by ғɪɴɴвαłσℜ
2

Aɴꜱᴡᴇʀ

Buoyant Force=10N

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Gɪᴠᴇɴ

Weight of ball = 4 kg

Density of ball = 4000 kgm³

Density of water= 1000 kgm³

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ᴛᴏ ꜰɪɴᴅ

The buoyant force?

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Sᴛᴇᴘꜱ

The buoyant force is given by

 \large \sf  \orange{f = pgv}

 \large \sf{}f =  \frac{4}{4000}  \times 10 \times 1000 \\  \\  \large \pink{ \dashrightarrow{} \tt{}f =  \huge \red{10n}}

Additional information:-

Buoyant : Buoyant force is an upward force exerted by a fluid, which opposes the weight of an object in the fluid. Objects immersed in water observes a loss in weight due to the buoyant force.

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\huge{\mathfrak{\purple{hope\; it \;helps}}}

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