Question

A ball when thrown vertically upwards, reaches a height of 40m. Find the velocity with which the ball is thrown upwards to reach this height and the time taken by it. (Take acceleration in the downward direction = 10 m/s^2)

Answer 1

Answer:

piyush Kumar kumar

Explanation:

√800

Answer 2

Answer:

Initial velocity, u = 28.284 m/s ≈ 28 m/s

Step-by-step explanation:

Given,

h = 40 m

g = 10 m / s²

By using the third equation of motion of falling bodies.

v² = u² + 2gh

where,

g = acceleration due to gravity.

h = displacement

u = intial velocity

v = final velocity

[°.° a = (-g) ]

Putting the given values in the equation.

=> v² = u² + 2gh

=> 0² = u² + 2 × (-10) × 40

=> u² = 800

=> u = √800

=> u = 28.284 m/s ≈ 28 m/s

.°. u = 28.284 m/s ≈ 28 m/s