A ball which is dropped from a height of 10 m rebounds to a height of 6 m and then continues to rebound to a height which is 3/5 of the previous height. What is the total distance the ball would have travelled before it comes to rest?
Answers
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Answer:
Hey there!! To answer your question, let me tell you what are fractions and how to add them.
What are fractions?
Ans. Fractions are nothing but numbers that have a numerator ( top part) and a denominator ( down part) , and both the numerator and denominator are numbers.
How do we add fractions?
Ans. To.add fractions, we first need to make sure that their denominators are the same. And, If not, we need to find the LCM of both the numbers and then multiply the numerator and denominator with the number that can make the required LCM number.
Then, we need to add only the numerator and keep the denominator as the LCM.
Step-by-step explanation:
So, following the rules of addition and the meaning of fraction , let us answer your question.
A ball which is dropped from a height of 10 m rebounds to a height of 6 m and then continues to rebound to a height which is 3/5 of the previous height. What is the total distance the ball would have travelled before it comes to rest?
Ans. So, If the ball has rebounded to a height that was 3/5th of the previous height, then the previous height was 6m.
So, we need to multiply 6 with 3/5 , to get how much is 3/5 th of 6.
So, 6×3/5=18/5m
Now, the total distance will be 10m+ 6m+ 18/5m
First, let us solve 10+ 6m. This is equal to 16m
Now , we need to solve 16+ 18/5.
Now since the denominator is not the same, we need to find the LCM. of 1 and 5( since if there is no denominator under a full number it means 1 can be put as the denominator) .
LCM of 1,5=5(Since they have no common multiples we need to multiply them together. 1×5=5.
So, it will become 80/5+18/5( workings in the picture)
= 98/5
98/5=19.6m is the total distance travelled.
Hope it helped!
Please mark as the brainliest answer!:)