a ball which is thrown upwards vertically returns to the earth after 8 seconds. find its position after 5 seconds.
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Answer:
t = 4s.
In 3 s, the ball reaches the maximum height and in 1 s it falls from the top.
Distance covered in 1 s from maximum height,
S = ut + 1/2at ²
S = 0 + 1/2 × 9.8 × 1
S = 4.9 m
Explanation:
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