a ball which is thrown vertically upwards rises to a height of 20m, calculate...
1. the velocity with which the ball is thrown upwards.
2. the time taken by the ball to reach the highest point (g=10m/s^-2)
Answers
hope it helps you mate.
please thank and Mark my answer as brainliest.
@ ANUSHA ❤✌
Answer
1 . Initial velocity , u = 20 m/s
2 . Time , t = 2 s
Given
- A ball which is thrown vertically upwards rises to a height of 20 m
To Find
1 . The velocity with which the ball is thrown upwards.
2 . the time taken by the ball to reach the highest point (g=10 m/s²)
Concept Used
We need to use equations of motion .
- v = u + at
- s = ut + ¹/₂ at²
- v² - u² = 2as
Solution
Height , s = 20 m
Here ball is thrown vertically upwards . So , at certain height the ball will go to rest . So ,
Final velocity , v = 0 m/s
Acceleration , a = g = - 10 m/s² [ Thrown against the gravity ]
Now , apply 3rd equation of motion .
⇒ v² - u² = 2as
⇒ 0² - u² = 2 ( - 10 ) ( 20 )
⇒ - u² = - 400
⇒ u² = 400
⇒ u = 20 m/s
1 . Initial velocity , u = 20 m/s
_______________________
Use 1st equation of motion .
⇒ v = u + at
⇒ 0 = 20 + ( - g ) t\\
⇒ 0 = 20 - 10t
⇒ 10t = 20
⇒ t = 2 s
2 . Time taken to reach the highest point , t = 2 s
__________________________