Question

a ball while rolling down an inclined plane as an acceleration of 4 cm per second square what will be its velocity 10 seconds after the start how much distance will it travel in 10 seconds ​

Answer 1

Answer:

a = 4 cm/s^2 = 0.04 m/s^2

t = 10 s

u = 0 m/s

s = ut + ½ at^2

= (0 + ½ x 0.04 x 10 x 10) m

= 10 m

v = u + at

= (0 + 0.04 x 10) m/s

= 0.4 m/s

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