a ball whose ke is E is projected at an angle of 45 to the horizontal .what will be kintic energyof a ball at heights point of flight
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Hey Blackdeath
your answer is here
velocity of particle at maximum height is
v = ucostheta
and initial velocity is v
at max height kinetic energy is kcos^theta
so ,
K = k× (1/root2)^2
K = k/2
Hope this help you
Thanks
Be Brainly
Mark me as Brainiest
your answer is here
velocity of particle at maximum height is
v = ucostheta
and initial velocity is v
at max height kinetic energy is kcos^theta
so ,
K = k× (1/root2)^2
K = k/2
Hope this help you
Thanks
Be Brainly
Mark me as Brainiest
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