Question

A ball whose kinetic energy is E is thrown at an angle of 45° with the horizontal. Its K. E. at the highest point of its flight will be :
a). E/√2
b). Zero
c). E
d). E/2

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Answer 1

Kinetic Energy, E = ½mv2

At the highest point, vertical component of velocity becomes zero and only the horizontal component is left that is given by

ux = u cosθ

θ = 45°, so cosθ = 1/√2

ux = u/√2

Kinetic energy E at the highest point = ½m(u/√2)2 = E/2

The correct option is D.

Brother I hope it's helpful!!!!

Answer 2

Answer is option (d).
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