a ball x of mass 1 kg traveling at 2 metre per second has head on collision with an identical balls while at rest x stops and y moves off calculate the velocity of y after the collision
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m1u1+m2u2=m1v1+m2v2
1×2+1×0=1×0+1×V2
2=V2
hence velocity of y is 2m/s
1×2+1×0=1×0+1×V2
2=V2
hence velocity of y is 2m/s
Draksha2224:
thanks brother
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