Question

A ball X of mass 1 kg travelling at 5 m/s has a
head-on collision with an identical ball Y at rest.
Ball X stops and ball Y moves off. Calculate the
velocity of ball Y after the collision.​

Answer 1

Answer:

Mass of the ball X, m

1

=1kg

Speed of ball X,u

1

=2m/s

Mass of ball y,m

2

=1kg

Speed of ball y,u

2

=0m/s(at rest)

Velocity of ball X after collision , v

1

=0m/s

Velocity of ball y after collision, v

2

Acc.to the law of conservation of momentum

m

1

u

1

+m

2

u

2

=m

1

v

1

+m

2

v

2

1×2+1×0=1×0+1×v

2

v

2

=

1

1×2

=2m/s

Explanation:

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Answer 2

Answer:

5m/sec

Explanation:

m1u1+m2u2 = m1v1+m2v2

1(5) = Y(v2)

Y(v2) = 5

if X ball stops after the collision then the Y ball should have same mass as that of X.

so, X= Y = 1kg

v2 = 5m/sec