Question

a Ball x of mass 1kg travelling at 10m/s has a head on collision with an identical ball y at rest. x stops and y moves off . calculate the velocity of yafter Collision​

Answer 1

Answer:

Mass of the ball X, m

1

=1kg

Speed of ball X,u

1

=2m/s

Mass of ball y,m

2

=1kg

Speed of ball y,u

2

=0m/s(at rest)

Velocity of ball X after collision , v

1

=0m/s

Velocity of ball y after collision, v

2

Acc.to the law of conservation of momentum

m

1

u

1

+m

2

u

2

=m

1

v

1

+m

2

v

2

1×2+1×0=1×0+1×v

2

v

2

=

1

1×2

=2m/s

Answer 2

Answer:

2 m/s

Explanation:

Answer:

2 m/s = v2

Explanation :

Ball 'X'

m1 (Mass) = 1 kg

u1 (Initial velocity) = 2 m/s

v1 (final velocity) = 0

Ball 'Y'

m2 = 1 kg

u2 = 0

v2 = ?

Using conservation of momentum

m1u1 × m2u2 = m1v1 + m2v2

1 * 2 + 1 * 0 = 1 * 0 + 1 * v2

2 = v2

v2 = 2 m/s

Therefore,

Final velocity of ball 'Y' is 2 m/s