A ball x of mass 1kg travelling at 2m/s has a head-on collision with an identical ball y at rest. X stops and y moves off.what is y' s velocity?
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Answer:
2 m/s = v2
Explanation :
Ball 'X'
m1 (Mass) = 1 kg
u1 (Initial velocity) = 2 m/s
v1 (final velocity) = 0
Ball 'Y'
m2 = 1 kg
u2 = 0
v2 = ?
Using conservation of momentum
m1u1 × m2u2 = m1v1 + m2v2
1 * 2 + 1 * 0 = 1 * 0 + 1 * v2
2 = v2
v2 = 2 m/s
Therefore,
Final velocity of ball 'Y' is 2 m/s
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