A ballis thrown vertically upward from ground when it is at 3/4th of its max ht its speed is 20 m/s.The speed of throw
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Explanation:After reaching the maximum height , it falls for 2seconds to reach the 25 m height.
Distance it has fallen is h = 0.5 gt^2 = 0.5*10* 4 =20 m.
Maximum height is 25+20 = 45 m.
Velocity at the bottom or the initial velocity is found from
u^2 = 2gh = 2*10*45 =900
u = 30 m/s.
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