Question

A balll is dropped from a height of 45m find time in which the body will hit the ground

Answer 1

Use formula

s = $(\frac{1}{2}a)(t^2)$

a- acceleration

t- time

Plug in numbers

(1/2 * 9.8)(t^2) = 45

9.8 * 1.2 = 4.9

4.9t^2 = 45

45/4.9= 9.1836

t^2= 9.1836

Square both sides

$\sqrt{t^2}=t$

$\sqrt{9.1836} = 3.03$

t= 3.03

Answer

It will take 3 seconds for the ball to hit the ground.