Question

A ballof 600g is kicked at an angle of 35 degree with an initial velocity v knot what is the initial velocity v knot of the ball if its kinetic energy is 22j when its height is maximum

Answer 1

Answer:

Explanation:

K.e=1/2 m (vknot cos35)^2

Vknot x cos35=sq root.44x0.6

Vknot=sq root.26.4/cos 35

Vknot= 6.272m/s (approx.)

Please tell me if I'm wrong.