Question

A ballon has 8g of air A small hole u penced
auto at the air escapes at a uniforms cate
of 7m/s. If the ballon shrinks in 5.6 es then
The average fonce acting on the ballon?​

Answer 1

$\checkmark$ Given:

A balloon has 8 gm of air. A small hole is pierced into it.

The air escapes at a uniform rate of 7 cm/s.

Balloon shrinks in 5.6 sec

$\checkmark$ To Find:

The average force acting on the balloon

$\checkmark$ Solution:

We know that,

$\red{\bigstar \ \boxed{\sf F=v \times \dfrac{dm}{dt}}}$

Here,

• F = Force,

• v = Velocity

• dm/dt = total rate of mass change

According to the question,

We are asked to find the the average force acting on the balloon

So, we must find "F"

Given that,

A balloon has 8 gm of air. A small hole is pierced into it.

The air escapes at a uniform rate of 7 cm/s.

Balloon shrinks in 5.6 sec

Hence,

• dm = 8 g

• v = 7 cm/s

• dt = 5.6 s

Substituting the values,

We get,

$\blue{\sf \implies F=7 \times \dfrac{8}{5.6} \ Dyne}$

$\green{\sf \implies F=7 \times 1.42857 \ Dyne}$

$\orange{\sf \implies F=10 \ Dyne}$

$\pink{\sf \implies F=10^{-4} \ N}$

Therefore,

Force = 10 Dyne (or) 10⁻⁴ N