Question

a ballon is moving in upward direction with constant velocity of 10 m/s. After 5s a stone is dropped from balloon . Find the time after which the stone will touch the ground​

Answer 1

Explanation:

speed of baloon =10m/s

distance of baloon after 5s =

s=d/t

10=d/5

d=50m

stone is dropped after 5 sec

acceleration due to gravity = approximately 10m/s

time = distance / speed

=50/10

5s

Answer 2

Answer:

2.31 seconds

Explanation:

Given:

• Constant velocity of the balloon = 10 m/s
• Time after which the stone is dropped = 5 seconds
• Acceleration due to gravity for stone = 10 m/s²

To find:

• Time taken for stone to touch the ground

The velocity of the balloon which is moving with a constant velocity of 10 m/s will be transferred to the stone's initial velocity

Height from which stone is dropped = 10×5=50 metres

Stone:

• Initial velocity = u = 10 m/s
• Acceleration = a = 10 m/s²
• Height of stone = s = 50 metres

Using second equation of motion:

$S=ut+\frac{1}{2} at^{2}$

$50=10 \times t + \frac{1}{2} \times 10 \times t^{2}$

$5 t^{2}+10t-50=0$

By solving the above equation we get ,

t=2.31 seconds (approx)

The time taken for the stone to fall down approximately is 2.31 seconds