Question

A balloon carrying a stone is moving upward with a constant speed 10 m/s. When balloon is at height 75 m, the stone is dropped. The time taken by the stone to reach the ground after release is (g = 10 m/s2)
(1) 4 s (2) 15 s (3) 5 s (4) 6 s

Answer 1

Answer:

A ballon moving upwards with constant velocity 10m/s . if we release the stone from ballon , then, initial speed of stone = 10m/sec .

now,

initial speed = 10m/sec

time = 11sec

let H is the height of ballon when stone is dropped .

use kinematics equation ,

S = Ut + 1/2at²

-H = 10 × 11 - 1/2 × 10 × (11)²

= 110 - 5× 121

= 110 - 605

= -495 m

- H = -495 m

hence, H = 495 m

so, height of ballon is 495m when stone is dropped .

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