Question

a balloon carrying a stone is moving with uniform speed 5m/s vertically upward. At stone instant, stone is dropped from the balloon and it strikes the ground after 10s of its release. The height from which stone was dropped is​

Answer 1

Answer:

answer is 500m

Explanation:

given,

u=5m/s(for going upward)

time of descent (i.e)the time to reach the ground=10s

a=10m/s^2(for convenience)

now for coming downward, u=0

so, use 2nd equation of motion to find height,

s=ut+1/2at^2

as u=0,

s=1/2at^2

s=1/2(10)(10)^2

s=1/2(10)(100)

s=1*5(100)

s=5(100)

s=500m

therefore, the height is 500m.

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