a balloon contain 0.02gram of hydrogen gas it contain hydrogen molecules
Answers
Answered by
1
Explanation:
From ideal gas equation PV=nRT,
Here, assume mass of helium in mixture is x, then mass of hydrogen is (5-x) so, 2×10
5
×0.02=((5−x)/2+x/4)8.314×293.
x=3.43and5−x=1.57.
So ratio of hydrogen to helium is 1:2.
then x+ y = 3
Answered by
1
Answer:
From ideal gas equation PV=nRT,
Here, assume mass of helium in mixture is x, then mass of hydrogen is (5-x) so, 2×10
5
×0.02=((5−x)/2+x/4)8.314×293.
x=3.43and5−x=1.57.
So ratio of hydrogen to helium is 1:2.
then x+ y = 3
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