Question

A balloon contains 146.0 mL of gas confined temperature of 1.30 atm and a temperature of 5.0°C. If the pressure doubles and the temperature decreases to 2.0°C, what will be the volume of gas in the balloon?

Answer 1

Answer:

The volume of gas when the pressure is doubled and the temperature is decreased to 2°C is 29.2 ml.

Explanation:

Step 1 : Write down the equation relating pressure, volume and temperature of gas.

The formula is given as :

(P1V1)/T1 = (P2V2) / T2

Where :

P = the pressure of the gas.

T = Temperature of the gas.

V = Volume of the gas.

Step 2: Identify the given information from the question.

V1 = 146.0 ml

P1 = 1.30atm

T1 = 5.0°C

V2 =?

T2 = 2.0°C

P2 = 1.30 × 2 = 2.60 atm

Step 3: Substitute the values in the formula.

(1.30 × 146.0)/5 = (2.60 × V2) / 2

189.8/5 = 2.60V2/2

2 × 189.8 = 2.60V2 × 5

379.6 = 13V2

V2 = 379.6/13

V2 = 29.2 ml

Step 4 : the answer

The volume of gas when the pressure is doubled and the temperature is decreased to 2°C is 29.2 ml.