A balloon contains 146.0 mL of gas confined temperature of 1.30 atm and a temperature of 5.0°C. If the pressure doubles and the temperature decreases to 2.0°C, what will be the volume of gas in the balloon?
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Answer:
The volume of gas when the pressure is doubled and the temperature is decreased to 2°C is 29.2 ml.
Explanation:
Step 1 : Write down the equation relating pressure, volume and temperature of gas.
The formula is given as :
(P1V1)/T1 = (P2V2) / T2
Where :
P = the pressure of the gas.
T = Temperature of the gas.
V = Volume of the gas.
Step 2: Identify the given information from the question.
V1 = 146.0 ml
P1 = 1.30atm
T1 = 5.0°C
V2 =?
T2 = 2.0°C
P2 = 1.30 × 2 = 2.60 atm
Step 3: Substitute the values in the formula.
(1.30 × 146.0)/5 = (2.60 × V2) / 2
189.8/5 = 2.60V2/2
2 × 189.8 = 2.60V2 × 5
379.6 = 13V2
V2 = 379.6/13
V2 = 29.2 ml
Step 4 : the answer
The volume of gas when the pressure is doubled and the temperature is decreased to 2°C is 29.2 ml.
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