Question

A balloon has 8gram of air A small hole is pierceid into the air escapes at a uniform rate 7cm/if the balloon shrinks 5.6sec then the average force acting on the balloon is​

Answer 1

Answer:

A balloon has 8g of air A small hole is pierced into it The air escapes at a unifrom rate of 7m//s If the ballon shrinks in 5.6 s then the average force acting on the ballon is. 10-4N .

Explanation:

F=7× 8/5.6

=10dynes=10 −4N

Answer 2

Answer:

The average thrust (force) acting on balloon is 0.01 N.

Explanation:

Given;-

     Mass of balloon, m = 8 g

Velocity of air (coming out), v = 7 m/s

     time period, t = 5.6 s

Let the average force (thrust) be 'F'.

We know that, by formula:-

    Force, F = mΔv/ Δt

               F = 8 × 7 / 1000 × 5.6

               F = 56/5600

               F = 0.01 N

Hence, the average thrust or force acting on the balloon is 0.01 N.

Hope it helps! ;-))