A balloon has a mass of 10 gram in air. the air escapes from the balloon at a uniform rate with a velocity of 5 cm/s and the balloon shrinks completely in 2.5 second.calculate average force acting on the balloon.
Answers
Answered by
39
As per the given question, mass = m = 10 g,
Velocity = v = 5 cm/s
Time taken = t = 2.5 s
We know,
force = vm / t = 5 x 10 / 2.5 = 20 g cm/ sec^2
Therefore, the average force acting on the balloon is equal to 20 g cm/ sec^2
Velocity = v = 5 cm/s
Time taken = t = 2.5 s
We know,
force = vm / t = 5 x 10 / 2.5 = 20 g cm/ sec^2
Therefore, the average force acting on the balloon is equal to 20 g cm/ sec^2
Answered by
0
Answer:
20 dyne Explanation: m = 10g v = 5 cm/s t = 2.5s force = F = (dp / dt) = (d / dt) (mv) i.e. F = (dm / dt) × (v) = {(10) / (2.5)} × 5 = 20 dyneRead
Similar questions