Physics, asked by gkhushboo630, 9 months ago

A balloon has volume 350L at 1.00 atm pressure. Its volume at constant temperature and 0.80 atm pressure will be?​

Answers

Answered by ronakavenger
0

Answer:

V1=175,p1=1bar,v2=?p2=0.80atm Therefore, By Boyle's law, P1v1=p2v2 =p1v1/p2 =1*175/0.80 =218.75L

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Answered by vankudremanasvi
17

Answer:

437L

Explanation:

Formula: p1v1=p2v2

p1: 1atm

v1: 350

p2: 0.80atm

v2:?

SO, 1*350=0.80*v2

350=0.80v2

350/0.80 = v2

437.5=v2

I hoped, i helped you :)

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