A balloon has volume 350L at 1.00 atm pressure. Its volume at constant temperature and 0.80 atm pressure will be?
Answers
Answered by
0
Answer:
V1=175,p1=1bar,v2=?p2=0.80atm Therefore, By Boyle's law, P1v1=p2v2 =p1v1/p2 =1*175/0.80 =218.75L
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Answered by
17
Answer:
437L
Explanation:
Formula: p1v1=p2v2
p1: 1atm
v1: 350
p2: 0.80atm
v2:?
SO, 1*350=0.80*v2
350=0.80v2
350/0.80 = v2
437.5=v2
I hoped, i helped you :)
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