A balloon is ascending at the rate of 9.8ms^(-1) at a height of 39.2m above the ground when a food packet is dropped from the balloon. After how much time and with what velocity does it reach the ground? Take g=9.8ms^(-2) .
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Answered by
3
Answer: (a) 4 s (b) 29.4 m/s
Explanation:
Taking downward direction +ve,u=−9.8m/s,s=39.2m and a=g=+9.8m/s2
(a) 39.2=−9.8t+12(9.8)t2
4.9t2−9.8t−39.2=0
t2−2t−8=0
(t−4)(t+2)=0
t=4s
(b) v=u+gt=−9.8×4=29.4m/s
Answered by
1
Answer: (a) 4 s (b) 29.4 m/s
Explanation:
Taking downward direction +ve,u=−9.8m/s,s=39.2m and a=g=+9.8m/s2
(a) 39.2=−9.8t+12(9.8)t2
4.9t2−9.8t−39.2=0
t2−2t−8=0
(t−4)(t+2)=0
t=4s
(b) v=u+gt=−9.8×4=29.4m/s
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