Question

a balloon is ascending up with a velocity of 4m/s. a object is dropped from it when it is at the height of 100m above the ground. distance between object and balloon after 2 seconds is

Answer 1

Answer:

Total distance between the balloon and the object after 2 seconds is 47.24m.

Explanation:

Given values,

Velocity, v= 4m/s

Height, h= 100m

Time, t= 2s

Gravity, g= 9.81m/s^2

After the object is dropped,

Distance travelled by the object,

s1=ut+(gt^2)/2

= 0+(9.81×4)/2

= 19.62 m

Distance travelled by the balloon,

s2=ut+(gt^2)/2

= (4×2)+(9.81×4)/2

= 8+19.62

= 27.62

Total distance between the balloon and the object after 2 seconds= s1+s2 = 19.62+27.62 = 47.24m.