a balloon is ascending up with a velocity of 4m/s. a object is dropped from it when it is at the height of 100m above the ground. distance between object and balloon after 2 seconds is
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Answer:
Total distance between the balloon and the object after 2 seconds is 47.24m.
Explanation:
Given values,
Velocity, v= 4m/s
Height, h= 100m
Time, t= 2s
Gravity, g= 9.81m/s^2
After the object is dropped,
Distance travelled by the object,
s1=ut+(gt^2)/2
= 0+(9.81×4)/2
= 19.62 m
Distance travelled by the balloon,
s2=ut+(gt^2)/2
= (4×2)+(9.81×4)/2
= 8+19.62
= 27.62
Total distance between the balloon and the object after 2 seconds= s1+s2 = 19.62+27.62 = 47.24m.
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