Question

A balloon is ascending vertically with a constant acceleration of 2 metre per second square two stones are dropped from it at an interval of 2 seconds find the distance between the two stones 1.5 second after second stone is dropped

Answer 1

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Answer 2

For the first stone,

a = 9.8 + 0.2 = 10 downwards,

Distance(D1) = 0.5 × 10 × 3.5 × 3.5

Similarly for the second stone,

D2 = 0.5 × 10 × 1.5 × 1.5

Therefore, D1 - D2 = 0.5 × 10 × 10 = 50m

Hope this helped ;-)