Question

A balloon is ascending vertically with an acceleration of 0.2m/s2, Two stones are dropped from it at an interval of 2 sec. Find the distance between them 1.5 sec after the second stone is released.(use g=9.8m/s2)

Answer 1

first u have to specify the velocity of balloon when stone is dropped,let it be v,velocity of 1st stone is v in upward direction n acceleration downward, usevt - 0.5 gt2 = d using appropriate signs for directions. t=2+1.5 secthe 2nd stone will have addition separation due to movement of balloon n also additional speeduse same formula with t=1.5 sec and v2 = v + time.acceleration of balloon*make a diagram with reference point as the place where 1st stone is drawn n measure distances accordingly