A balloon is ascending with a velocity of 9.8ms^-1, a sand bag dropped from the balloon when it is at a height of 39.2m from the ground calculate the time taken by bag to reach the ground
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Correct answer 4s
Packet acquire the ballon velocity after it is dropped
−39.2 = 9.8t− 1/2 gt sq
⇒5t sq −9.8t−39.2 = 0
t= 109.8 + /(9.8) 2+4×39.2×5) [ / ) = root sign ]
<this all divide by 10>
=3.94 sec ≈4 sec
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